Base | Representation |
---|---|
bin | 111101011110011110… |
… | …1101011101011100111 |
3 | 110121202122121120120222 |
4 | 1322330331223223213 |
5 | 4130333420231231 |
6 | 140352051514555 |
7 | 12352363402334 |
oct | 1727475535347 |
9 | 417678546528 |
10 | 132019305191 |
11 | 50a97501aa4 |
12 | 21704bb8a5b |
13 | c5ac34ac87 |
14 | 656574b98b |
15 | 367a28b27b |
hex | 1ebcf6bae7 |
132019305191 has 2 divisors, whose sum is σ = 132019305192. Its totient is φ = 132019305190.
The previous prime is 132019305179. The next prime is 132019305289. The reversal of 132019305191 is 191503910231.
It is a weak prime.
It is an emirp because it is prime and its reverse (191503910231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132019305191 - 26 = 132019305127 is a prime.
It is a super-2 number, since 2×1320193051912 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132019305151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66009652595 + 66009652596.
It is an arithmetic number, because the mean of its divisors is an integer number (66009652596).
Almost surely, 2132019305191 is an apocalyptic number.
132019305191 is a deficient number, since it is larger than the sum of its proper divisors (1).
132019305191 is an equidigital number, since it uses as much as digits as its factorization.
132019305191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7290, while the sum is 35.
The spelling of 132019305191 in words is "one hundred thirty-two billion, nineteen million, three hundred five thousand, one hundred ninety-one".
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