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132019541 is a prime number
BaseRepresentation
bin1111101111001…
…11010101010101
3100012102021202122
413313213111111
5232244111131
621033345325
73162101423
oct767472525
9305367678
10132019541
1168581265
1238268245
1321474a94
1413768113
15b8cbd7b
hex7de7555

132019541 has 2 divisors, whose sum is σ = 132019542. Its totient is φ = 132019540.

The previous prime is 132019523. The next prime is 132019553. The reversal of 132019541 is 145910231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125664100 + 6355441 = 11210^2 + 2521^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132019541 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132019541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132019561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66009770 + 66009771.

It is an arithmetic number, because the mean of its divisors is an integer number (66009771).

Almost surely, 2132019541 is an apocalyptic number.

It is an amenable number.

132019541 is a deficient number, since it is larger than the sum of its proper divisors (1).

132019541 is an equidigital number, since it uses as much as digits as its factorization.

132019541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 26.

The square root of 132019541 is about 11489.9756744738. The cubic root of 132019541 is about 509.1894609290.

Adding to 132019541 its reverse (145910231), we get a palindrome (277929772).

The spelling of 132019541 in words is "one hundred thirty-two million, nineteen thousand, five hundred forty-one".