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13202001341206 = 28211318038913
BaseRepresentation
bin1100000000011101010010…
…0110011010101100010110
31201202002200011122212210021
43000013110212122230112
53212300144320404311
644024525442215354
72531545620564406
oct300072446325426
951662604585707
1013202001341206
11422aa34644197
12159277765455a
13749c35801252
14338da1c30806
1517d633686171
hexc01d499ab16

13202001341206 has 8 divisors (see below), whose sum is σ = 19803028591944. Its totient is φ = 6600991810560.

The previous prime is 13202001341201. The next prime is 13202001341219. The reversal of 13202001341206 is 60214310020231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13202001341201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2377195 + ... + 5661718.

It is an arithmetic number, because the mean of its divisors is an integer number (2475378573993).

Almost surely, 213202001341206 is an apocalyptic number.

13202001341206 is a deficient number, since it is larger than the sum of its proper divisors (6601027250738).

13202001341206 is an equidigital number, since it uses as much as digits as its factorization.

13202001341206 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8860046.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13202001341206 its reverse (60214310020231), we get a palindrome (73416311361437).

The spelling of 13202001341206 in words is "thirteen trillion, two hundred two billion, one million, three hundred forty-one thousand, two hundred six".

Divisors: 1 2 821131 1642262 8038913 16077826 6601000670603 13202001341206