Base | Representation |
---|---|
bin | 11110000001001001010011… |
… | …001110101110010101110010 |
3 | 122022102222221211122111020001 |
4 | 132001021103032232111302 |
5 | 114301004131341110302 |
6 | 1144441110331340214 |
7 | 36544065114643231 |
oct | 3601112316562562 |
9 | 568388854574201 |
10 | 132020101113202 |
11 | 3907a457359965 |
12 | 129824688b166a |
13 | 5888599437583 |
14 | 2485b42534b18 |
15 | 103e22c116787 |
hex | 7812533ae572 |
132020101113202 has 4 divisors (see below), whose sum is σ = 198030151669806. Its totient is φ = 66010050556600.
The previous prime is 132020101113169. The next prime is 132020101113227. The reversal of 132020101113202 is 202311101020231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 67129198084081 + 64890903029121 = 8193241^2 + 8055489^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 132020101113202.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33005025278299 + ... + 33005025278302.
Almost surely, 2132020101113202 is an apocalyptic number.
132020101113202 is a deficient number, since it is larger than the sum of its proper divisors (66010050556604).
132020101113202 is an equidigital number, since it uses as much as digits as its factorization.
132020101113202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66010050556603.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 132020101113202 its reverse (202311101020231), we get a palindrome (334331202133433).
The spelling of 132020101113202 in words is "one hundred thirty-two trillion, twenty billion, one hundred one million, one hundred thirteen thousand, two hundred two".
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