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132020101113202 = 266010050556601
BaseRepresentation
bin11110000001001001010011…
…001110101110010101110010
3122022102222221211122111020001
4132001021103032232111302
5114301004131341110302
61144441110331340214
736544065114643231
oct3601112316562562
9568388854574201
10132020101113202
113907a457359965
12129824688b166a
135888599437583
142485b42534b18
15103e22c116787
hex7812533ae572

132020101113202 has 4 divisors (see below), whose sum is σ = 198030151669806. Its totient is φ = 66010050556600.

The previous prime is 132020101113169. The next prime is 132020101113227. The reversal of 132020101113202 is 202311101020231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 67129198084081 + 64890903029121 = 8193241^2 + 8055489^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 132020101113202.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33005025278299 + ... + 33005025278302.

Almost surely, 2132020101113202 is an apocalyptic number.

132020101113202 is a deficient number, since it is larger than the sum of its proper divisors (66010050556604).

132020101113202 is an equidigital number, since it uses as much as digits as its factorization.

132020101113202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66010050556603.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 132020101113202 its reverse (202311101020231), we get a palindrome (334331202133433).

The spelling of 132020101113202 in words is "one hundred thirty-two trillion, twenty billion, one hundred one million, one hundred thirteen thousand, two hundred two".

Divisors: 1 2 66010050556601 132020101113202