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13202013113 is a prime number
BaseRepresentation
bin11000100101110011…
…01011101110111001
31021002001220202100122
430102321223232321
5204014203404423
610022004543025
7645105155102
oct142271535671
937061822318
1013202013113
115665212943
1226853b1a75
1313251b23a3
148d35133a9
155240578c8
hex312e6bbb9

13202013113 has 2 divisors, whose sum is σ = 13202013114. Its totient is φ = 13202013112.

The previous prime is 13202013107. The next prime is 13202013131. The reversal of 13202013113 is 31131020231.

Together with next prime (13202013131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13200171664 + 1841449 = 114892^2 + 1357^2 .

It is a cyclic number.

It is not a de Polignac number, because 13202013113 - 26 = 13202013049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13202013091 and 13202013100.

It is not a weakly prime, because it can be changed into another prime (13202013103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601006556 + 6601006557.

It is an arithmetic number, because the mean of its divisors is an integer number (6601006557).

Almost surely, 213202013113 is an apocalyptic number.

It is an amenable number.

13202013113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13202013113 is an equidigital number, since it uses as much as digits as its factorization.

13202013113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13202013113 its reverse (31131020231), we get a palindrome (44333033344).

The spelling of 13202013113 in words is "thirteen billion, two hundred two million, thirteen thousand, one hundred thirteen".