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132020154312434 = 2611082132412397
BaseRepresentation
bin11110000001001001010110…
…011001101010011011110010
3122022110000002112202021211222
4132001021112121222123302
5114301004234000444214
61144441115511505042
736544066332064103
oct3601112631523362
9568400075667758
10132020154312434
113907a484395273
1212982482688182
1358885a7472bcb
142485b496223aa
15103e231b2438e
hex78125666a6f2

132020154312434 has 8 divisors (see below), whose sum is σ = 201276628706028. Its totient is φ = 64927944743760.

The previous prime is 132020154312427. The next prime is 132020154312463. The reversal of 132020154312434 is 434213451020231.

It can be written as a sum of positive squares in 2 ways, for example, as 124399379981809 + 7620774330625 = 11153447^2 + 2760575^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1320201543124342 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132020154312394 and 132020154312403.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 541066206077 + ... + 541066206320.

Almost surely, 2132020154312434 is an apocalyptic number.

132020154312434 is a deficient number, since it is larger than the sum of its proper divisors (69256474393594).

132020154312434 is a wasteful number, since it uses less digits than its factorization.

132020154312434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1082132412460.

The product of its (nonzero) digits is 69120, while the sum is 35.

The spelling of 132020154312434 in words is "one hundred thirty-two trillion, twenty billion, one hundred fifty-four million, three hundred twelve thousand, four hundred thirty-four".

Divisors: 1 2 61 122 1082132412397 2164264824794 66010077156217 132020154312434