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132020154312451 = 235740006709237
BaseRepresentation
bin11110000001001001010110…
…011001101010011100000011
3122022110000002112202021212121
4132001021112121222130003
5114301004234000444301
61144441115511505111
736544066332064126
oct3601112631523403
9568400075667777
10132020154312451
113907a484395289
1212982482688197
1358885a7472c12
142485b496223bd
15103e231b243a1
hex78125666a703

132020154312451 has 4 divisors (see below), whose sum is σ = 137760161021712. Its totient is φ = 126280147603192.

The previous prime is 132020154312427. The next prime is 132020154312463. The reversal of 132020154312451 is 154213451020231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132020154312451 - 25 = 132020154312419 is a prime.

It is a super-2 number, since 2×1320201543124512 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132020154412451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2870003354596 + ... + 2870003354641.

It is an arithmetic number, because the mean of its divisors is an integer number (34440040255428).

Almost surely, 2132020154312451 is an apocalyptic number.

132020154312451 is a deficient number, since it is larger than the sum of its proper divisors (5740006709261).

132020154312451 is an equidigital number, since it uses as much as digits as its factorization.

132020154312451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5740006709260.

The product of its (nonzero) digits is 28800, while the sum is 34.

The spelling of 132020154312451 in words is "one hundred thirty-two trillion, twenty billion, one hundred fifty-four million, three hundred twelve thousand, four hundred fifty-one".

Divisors: 1 23 5740006709237 132020154312451