132020154313001 has 4 divisors (see below), whose sum is σ = 132021717820752. Its totient is φ = 132018590805252.

The previous prime is 132020154312961. The next prime is 132020154313093. The reversal of 132020154313001 is 100313451020231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132020154313001 is a prime.

It is a super-3 number, since 3×132020154313001³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132020154343001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 781627211 + ... + 781796096.

It is an arithmetic number, because the mean of its divisors is an integer number (33005429455188).

Almost surely, 2^{132020154313001} is an apocalyptic number.

It is an amenable number.

132020154313001 is a deficient number, since it is larger than the sum of its proper divisors (1563507751).

132020154313001 is an equidigital number, since it uses as much as digits as its factorization.

132020154313001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1563507750.

The product of its (nonzero) digits is 2160, while the sum is 26.

The spelling of 132020154313001 in words is "one hundred thirty-two trillion, twenty billion, one hundred fifty-four million, three hundred thirteen thousand, one".