Base | Representation |
---|---|
bin | 10011001101100010001… |
… | …011000000000111011101 |
3 | 11200012200010222221121112 |
4 | 103031202023000013131 |
5 | 133112233203323401 |
6 | 2450254210511405 |
7 | 164244556640051 |
oct | 23154213000735 |
9 | 4605603887545 |
10 | 1320202011101 |
11 | 469992688136 |
12 | 193a44b95565 |
13 | 976575b186c |
14 | 47c80617c61 |
15 | 2451c7963bb |
hex | 133622c01dd |
1320202011101 has 4 divisors (see below), whose sum is σ = 1320729461472. Its totient is φ = 1319674560732.
The previous prime is 1320202011041. The next prime is 1320202011109. The reversal of 1320202011101 is 1011102020231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1320202011101 - 234 = 1303022141917 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1320202011109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 263721431 + ... + 263726436.
It is an arithmetic number, because the mean of its divisors is an integer number (330182365368).
Almost surely, 21320202011101 is an apocalyptic number.
It is an amenable number.
1320202011101 is a deficient number, since it is larger than the sum of its proper divisors (527450371).
1320202011101 is an equidigital number, since it uses as much as digits as its factorization.
1320202011101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 527450370.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1320202011101 its reverse (1011102020231), we get a palindrome (2331304031332).
The spelling of 1320202011101 in words is "one trillion, three hundred twenty billion, two hundred two million, eleven thousand, one hundred one".
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