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132020244244412 = 2233005061061103
BaseRepresentation
bin11110000001001001011011…
…110000101110011110111100
3122022110000022210222022022222
4132001021123300232132330
5114301004430011310122
61144441132443224512
736544101503354336
oct3601113360563674
9568400283868288
10132020244244412
113907a52012a517
12129824a8818138
1358885bcc9cbb4
142485b57552456
15103e23998ab42
hex78125bc2e7bc

132020244244412 has 6 divisors (see below), whose sum is σ = 231035427427728. Its totient is φ = 66010122122204.

The previous prime is 132020244244409. The next prime is 132020244244477. The reversal of 132020244244412 is 214442442020231.

It is a super-3 number, since 3×1320202442444123 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16502530530548 + ... + 16502530530555.

It is an arithmetic number, because the mean of its divisors is an integer number (38505904571288).

Almost surely, 2132020244244412 is an apocalyptic number.

It is an amenable number.

132020244244412 is a deficient number, since it is larger than the sum of its proper divisors (99015183183316).

132020244244412 is a wasteful number, since it uses less digits than its factorization.

132020244244412 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33005061061107 (or 33005061061105 counting only the distinct ones).

The product of its (nonzero) digits is 98304, while the sum is 35.

Adding to 132020244244412 its reverse (214442442020231), we get a palindrome (346462686264643).

The spelling of 132020244244412 in words is "one hundred thirty-two trillion, twenty billion, two hundred forty-four million, two hundred forty-four thousand, four hundred twelve".

Divisors: 1 2 4 33005061061103 66010122122206 132020244244412