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13202040133 is a prime number
BaseRepresentation
bin11000100101110011…
…10010010101000101
31021002001222010102101
430102321302111011
5204014210241013
610022005312101
7645105326632
oct142271622505
937061863371
1013202040133
115665231177
122685405631
1313251c1789
148d351d189
155240608dd
hex312e72545

13202040133 has 2 divisors, whose sum is σ = 13202040134. Its totient is φ = 13202040132.

The previous prime is 13202040121. The next prime is 13202040143. The reversal of 13202040133 is 33104020231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13137285924 + 64754209 = 114618^2 + 8047^2 .

It is a cyclic number.

It is not a de Polignac number, because 13202040133 - 25 = 13202040101 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13202040133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13202040143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601020066 + 6601020067.

It is an arithmetic number, because the mean of its divisors is an integer number (6601020067).

Almost surely, 213202040133 is an apocalyptic number.

It is an amenable number.

13202040133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13202040133 is an equidigital number, since it uses as much as digits as its factorization.

13202040133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 13202040133 its reverse (33104020231), we get a palindrome (46306060364).

The spelling of 13202040133 in words is "thirteen billion, two hundred two million, forty thousand, one hundred thirty-three".