1320204410341 has 4 divisors (see below), whose sum is σ = 1333021928992. Its totient is φ = 1307386891692.

The previous prime is 1320204410297. The next prime is 1320204410347. The reversal of 1320204410341 is 1430144020231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1320204410341 - 2¹⁵ = 1320204377573 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320204410347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6408759171 + ... + 6408759376.

It is an arithmetic number, because the mean of its divisors is an integer number (333255482248).

Almost surely, 2^{1320204410341} is an apocalyptic number.

It is an amenable number.

1320204410341 is a deficient number, since it is larger than the sum of its proper divisors (12817518651).

1320204410341 is a wasteful number, since it uses less digits than its factorization.

1320204410341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12817518650.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1320204410341 its reverse (1430144020231), we get a palindrome (2750348430572).

The spelling of 1320204410341 in words is "one trillion, three hundred twenty billion, two hundred four million, four hundred ten thousand, three hundred forty-one".