1320204411312 has 40 divisors (see below), whose sum is σ = 3410616081600. Its totient is φ = 440056779840.

The previous prime is 1320204411283. The next prime is 1320204411341. The reversal of 1320204411312 is 2131144020231.

It is an interprime number because it is at equal distance from previous prime (1320204411283) and next prime (1320204411341).

It is a super-2 number, since 2×1320204411312² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1639939 + ... + 2308637.

It is an arithmetic number, because the mean of its divisors is an integer number (85265402040).

Almost surely, 2^{1320204411312} is an apocalyptic number.

1320204411312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1320204411312 is an abundant number, since it is smaller than the sum of its proper divisors (2090411670288).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1320204411312 is a wasteful number, since it uses less digits than its factorization.

1320204411312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 709841 (or 709835 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 1320204411312 its reverse (2131144020231), we get a palindrome (3451348431543).

The spelling of 1320204411312 in words is "one trillion, three hundred twenty billion, two hundred four million, four hundred eleven thousand, three hundred twelve".