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13202100433 = 83962916519
BaseRepresentation
bin11000100101110100…
…00001000011010001
31021002002002012010201
430102322001003101
5204014214203213
610022010455201
7645106000504
oct142272010321
937062065121
1013202100433
115665272505
122685434501
131325213062
148d353713b
155240736dd
hex312e810d1

13202100433 has 8 divisors (see below), whose sum is σ = 13363358400. Its totient is φ = 13040894928.

The previous prime is 13202100419. The next prime is 13202100451. The reversal of 13202100433 is 33400120231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-13202100433 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13202100433.

It is not an unprimeable number, because it can be changed into a prime (13202100463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 790948 + ... + 807466.

It is an arithmetic number, because the mean of its divisors is an integer number (1670419800).

Almost surely, 213202100433 is an apocalyptic number.

It is an amenable number.

13202100433 is a deficient number, since it is larger than the sum of its proper divisors (161257967).

13202100433 is an equidigital number, since it uses as much as digits as its factorization.

13202100433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26231.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 13202100433 its reverse (33400120231), we get a palindrome (46602220664).

The spelling of 13202100433 in words is "thirteen billion, two hundred two million, one hundred thousand, four hundred thirty-three".

Divisors: 1 83 9629 16519 799207 1371077 159061451 13202100433