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132021040140113 = 976072242243247
BaseRepresentation
bin11110000001001010001011…
…001100110100111101010001
3122022110002101021120222222112
4132001022023030310331101
5114301013042233440423
61144441343434115105
736544130306355065
oct3601121314647521
9568402337528875
10132021040140113
113907a899417763
121298268b27ba95
1358886b8b468b7
142485bd112daa5
15103e2847a1a78
hex78128b334f51

132021040140113 has 8 divisors (see below), whose sum is σ = 133601821688832. Its totient is φ = 130444743079296.

The previous prime is 132021040140107. The next prime is 132021040140139. The reversal of 132021040140113 is 311041040120231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132021040140113 - 24 = 132021040140097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132021040146113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1121062745 + ... + 1121180502.

It is an arithmetic number, because the mean of its divisors is an integer number (16700227711104).

Almost surely, 2132021040140113 is an apocalyptic number.

It is an amenable number.

132021040140113 is a deficient number, since it is larger than the sum of its proper divisors (1580781548719).

132021040140113 is an equidigital number, since it uses as much as digits as its factorization.

132021040140113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2242243951.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 132021040140113 its reverse (311041040120231), we get a palindrome (443062080260344).

The spelling of 132021040140113 in words is "one hundred thirty-two trillion, twenty-one billion, forty million, one hundred forty thousand, one hundred thirteen".

Divisors: 1 97 607 58879 2242243247 217497594959 1361041650929 132021040140113