13202112000000 has 2912 divisors, whose sum is σ = 58974445117440. Its totient is φ = 2543616000000.

The previous prime is 13202111999957. The next prime is 13202112000001. The reversal of 13202112000000 is 21120231.

It is a super-2 number, since 2×13202112000000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 13202112000000.

It is not an unprimeable number, because it can be changed into a prime (13202112000001) by changing a digit.

It is a polite number, since it can be written in 223 ways as a sum of consecutive naturals, for example, 280895999977 + ... + 280896000023.

Almost surely, 2^{13202112000000} is an apocalyptic number.

13202112000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13202112000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29487222558720).

13202112000000 is an abundant number, since it is smaller than the sum of its proper divisors (45772333117440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13202112000000 is an frugal number, since it uses more digits than its factorization.

13202112000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 141 (or 94 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 13202112000000 its reverse (21120231), we get a palindrome (13202133120231).

The spelling of 13202112000000 in words is "thirteen trillion, two hundred two billion, one hundred twelve million", and thus it is an aban number.