Base | Representation |
---|---|
bin | 11110000001001011000100… |
… | …100010100000101010100111 |
3 | 122022110011212022201220211011 |
4 | 132001023010202200222213 |
5 | 114301022030021003404 |
6 | 1144442023120523051 |
7 | 36544163200200124 |
oct | 3601130442405247 |
9 | 568404768656734 |
10 | 132022002125479 |
11 | 39080242436594 |
12 | 129828b9480487 |
13 | 5888810233acb |
14 | 2485c82bc374b |
15 | 103e2dde74604 |
hex | 7812c48a0aa7 |
132022002125479 has 2 divisors, whose sum is σ = 132022002125480. Its totient is φ = 132022002125478.
The previous prime is 132022002125473. The next prime is 132022002125617. The reversal of 132022002125479 is 974521200220231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132022002125479 - 213 = 132022002117287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132022002125473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66011001062739 + 66011001062740.
It is an arithmetic number, because the mean of its divisors is an integer number (66011001062740).
Almost surely, 2132022002125479 is an apocalyptic number.
132022002125479 is a deficient number, since it is larger than the sum of its proper divisors (1).
132022002125479 is an equidigital number, since it uses as much as digits as its factorization.
132022002125479 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 40.
The spelling of 132022002125479 in words is "one hundred thirty-two trillion, twenty-two billion, two million, one hundred twenty-five thousand, four hundred seventy-nine".
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