Base | Representation |
---|---|
bin | 10011001101100011011… |
… | …100010010100010011111 |
3 | 11200012201122002120020021 |
4 | 103031203130102202133 |
5 | 133112304132221343 |
6 | 2450300251333011 |
7 | 164245236030553 |
oct | 23154334224237 |
9 | 4605648076207 |
10 | 1320223320223 |
11 | 4699a3711a85 |
12 | 193a50151167 |
13 | 9765bb32b02 |
14 | 47c833a3863 |
15 | 2451e5a50ed |
hex | 1336371289f |
1320223320223 has 4 divisors (see below), whose sum is σ = 1320232219720. Its totient is φ = 1320214420728.
The previous prime is 1320223320217. The next prime is 1320223320239. The reversal of 1320223320223 is 3220233220231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320223320223 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1320223320203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4223388 + ... + 4525201.
It is an arithmetic number, because the mean of its divisors is an integer number (330058054930).
Almost surely, 21320223320223 is an apocalyptic number.
1320223320223 is a deficient number, since it is larger than the sum of its proper divisors (8899497).
1320223320223 is an equidigital number, since it uses as much as digits as its factorization.
1320223320223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8899496.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 1320223320223 its reverse (3220233220231), we get a palindrome (4540456540454).
The spelling of 1320223320223 in words is "one trillion, three hundred twenty billion, two hundred twenty-three million, three hundred twenty thousand, two hundred twenty-three".
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