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13202241145217 is a prime number
BaseRepresentation
bin1100000000011110001011…
…1001001100100110000001
31201202010021212220012001022
43000013202321030212001
53212301142213121332
644025005330115225
72531554562102435
oct300074271144601
951663255805038
1013202241145217
114230047a43523
121592823a1bb15
13749c733b3b07
14338dc5a149c5
1517d649754212
hexc01e2e4c981

13202241145217 has 2 divisors, whose sum is σ = 13202241145218. Its totient is φ = 13202241145216.

The previous prime is 13202241145099. The next prime is 13202241145277. The reversal of 13202241145217 is 71254114220231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12765585826816 + 436655318401 = 3572896^2 + 660799^2 .

It is a cyclic number.

It is not a de Polignac number, because 13202241145217 - 236 = 13133521668481 is a prime.

It is not a weakly prime, because it can be changed into another prime (13202241145277) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601120572608 + 6601120572609.

It is an arithmetic number, because the mean of its divisors is an integer number (6601120572609).

Almost surely, 213202241145217 is an apocalyptic number.

It is an amenable number.

13202241145217 is a deficient number, since it is larger than the sum of its proper divisors (1).

13202241145217 is an equidigital number, since it uses as much as digits as its factorization.

13202241145217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26880, while the sum is 35.

Adding to 13202241145217 its reverse (71254114220231), we get a palindrome (84456355365448).

The spelling of 13202241145217 in words is "thirteen trillion, two hundred two billion, two hundred forty-one million, one hundred forty-five thousand, two hundred seventeen".