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1320231013117 is a prime number
BaseRepresentation
bin10011001101100011111…
…001101000101011111101
311200012202011120101220021
4103031203321220223331
5133112313114404432
62450301124252141
7164245361311042
oct23154371505375
94605664511807
101320231013117
114699a7a96845
12193a52841051
13976605c7513
1447c844071c9
15245200c4697
hex13363e68afd

1320231013117 has 2 divisors, whose sum is σ = 1320231013118. Its totient is φ = 1320231013116.

The previous prime is 1320231013091. The next prime is 1320231013141. The reversal of 1320231013117 is 7113101320231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1002573653796 + 317657359321 = 1001286^2 + 563611^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320231013117 - 223 = 1320222624509 is a prime.

It is a super-3 number, since 3×13202310131173 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1320231013091 and 1320231013100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320231013187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660115506558 + 660115506559.

It is an arithmetic number, because the mean of its divisors is an integer number (660115506559).

Almost surely, 21320231013117 is an apocalyptic number.

It is an amenable number.

1320231013117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320231013117 is an equidigital number, since it uses as much as digits as its factorization.

1320231013117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 1320231013117 its reverse (7113101320231), we get a palindrome (8433332333348).

The spelling of 1320231013117 in words is "one trillion, three hundred twenty billion, two hundred thirty-one million, thirteen thousand, one hundred seventeen".