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132023323308131 is a prime number
BaseRepresentation
bin11110000001001100010011…
…010010011011000001100011
3122022110022021101202221200222
4132001030103102123001203
5114301032231231330011
61144442402154233255
736544241012103443
oct3601142322330143
9568408241687628
10132023323308131
1139080860191682
1212983007a2582b
135888990b775a8
142485d6a45a123
15103e369e4addb
hex78131349b063

132023323308131 has 2 divisors, whose sum is σ = 132023323308132. Its totient is φ = 132023323308130.

The previous prime is 132023323308061. The next prime is 132023323308187. The reversal of 132023323308131 is 131803323320231.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132023323308131 - 226 = 132023256199267 is a prime.

It is a super-2 number, since 2×1320233233081312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132023323308091 and 132023323308100.

It is not a weakly prime, because it can be changed into another prime (132023323308931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66011661654065 + 66011661654066.

It is an arithmetic number, because the mean of its divisors is an integer number (66011661654066).

Almost surely, 2132023323308131 is an apocalyptic number.

132023323308131 is a deficient number, since it is larger than the sum of its proper divisors (1).

132023323308131 is an equidigital number, since it uses as much as digits as its factorization.

132023323308131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 35.

Adding to 132023323308131 its reverse (131803323320231), we get a palindrome (263826646628362).

The spelling of 132023323308131 in words is "one hundred thirty-two trillion, twenty-three billion, three hundred twenty-three million, three hundred eight thousand, one hundred thirty-one".