Base | Representation |
---|---|
bin | 111101011110100110… |
… | …1011101101111111111 |
3 | 110121202221101202211002 |
4 | 1322331031131233333 |
5 | 4130341000124211 |
6 | 140352320320515 |
7 | 12352443513266 |
oct | 1727515355777 |
9 | 417687352732 |
10 | 132023442431 |
11 | 50a99878401 |
12 | 2170647313b |
13 | c5b016914a |
14 | 65661075dd |
15 | 367a80703b |
hex | 1ebd35dbff |
132023442431 has 2 divisors, whose sum is σ = 132023442432. Its totient is φ = 132023442430.
The previous prime is 132023442409. The next prime is 132023442437. The reversal of 132023442431 is 134244320231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132023442431 - 26 = 132023442367 is a prime.
It is a super-2 number, since 2×1320234424312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132023442394 and 132023442403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132023442437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66011721215 + 66011721216.
It is an arithmetic number, because the mean of its divisors is an integer number (66011721216).
Almost surely, 2132023442431 is an apocalyptic number.
132023442431 is a deficient number, since it is larger than the sum of its proper divisors (1).
132023442431 is an equidigital number, since it uses as much as digits as its factorization.
132023442431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 132023442431 its reverse (134244320231), we get a palindrome (266267762662).
The spelling of 132023442431 in words is "one hundred thirty-two billion, twenty-three million, four hundred forty-two thousand, four hundred thirty-one".
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