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1320240411401 = 9737271355863
BaseRepresentation
bin10011001101100100011…
…101011111001100001001
311200012202211020212220212
4103031210131133030021
5133112323021131101
62450302101530505
7164245534223222
oct23154435371411
94605684225825
101320240411401
11469a0232591a
12193a55a13a35
1397662538232
1447c85772249
1524520d2e1bb
hex1336475f309

1320240411401 has 4 divisors (see below), whose sum is σ = 1320242740992. Its totient is φ = 1320238081812.

The previous prime is 1320240411353. The next prime is 1320240411403. The reversal of 1320240411401 is 1041140420231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1320240411401 - 218 = 1320240149257 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1320240411403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 295796 + ... + 1651658.

It is an arithmetic number, because the mean of its divisors is an integer number (330060685248).

Almost surely, 21320240411401 is an apocalyptic number.

It is an amenable number.

1320240411401 is a deficient number, since it is larger than the sum of its proper divisors (2329591).

1320240411401 is an equidigital number, since it uses as much as digits as its factorization.

1320240411401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2329590.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1320240411401 its reverse (1041140420231), we get a palindrome (2361380831632).

The spelling of 1320240411401 in words is "one trillion, three hundred twenty billion, two hundred forty million, four hundred eleven thousand, four hundred one".

Divisors: 1 973727 1355863 1320240411401