Base | Representation |
---|---|
bin | 11000100101110110… |
… | …10100110010001011 |
3 | 1021002002201121121022 |
4 | 30102323110302023 |
5 | 204014311142103 |
6 | 10022022103055 |
7 | 645111626432 |
oct | 142273246213 |
9 | 37062647538 |
10 | 13202443403 |
11 | 5665487156 |
12 | 268557aa8b |
13 | 13253031b6 |
14 | 8d35c6119 |
15 | 5240e0138 |
hex | 312ed4c8b |
13202443403 has 2 divisors, whose sum is σ = 13202443404. Its totient is φ = 13202443402.
The previous prime is 13202443391. The next prime is 13202443433. The reversal of 13202443403 is 30434420231.
13202443403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13202443403 - 28 = 13202443147 is a prime.
It is not a weakly prime, because it can be changed into another prime (13202443433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601221701 + 6601221702.
It is an arithmetic number, because the mean of its divisors is an integer number (6601221702).
Almost surely, 213202443403 is an apocalyptic number.
13202443403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13202443403 is an equidigital number, since it uses as much as digits as its factorization.
13202443403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 13202443403 its reverse (30434420231), we get a palindrome (43636863634).
The spelling of 13202443403 in words is "thirteen billion, two hundred two million, four hundred forty-three thousand, four hundred three".
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