Base | Representation |
---|---|
bin | 11000100101110110… |
… | …10110101010111111 |
3 | 1021002002202000012200 |
4 | 30102323112222333 |
5 | 204014311414020 |
6 | 10022022202543 |
7 | 645111661116 |
oct | 142273265277 |
9 | 37062660180 |
10 | 13202451135 |
11 | 5665491a45 |
12 | 2685583453 |
13 | 1325306883 |
14 | 8d35c8c7d |
15 | 5240e2590 |
hex | 312ed6abf |
13202451135 has 48 divisors (see below), whose sum is σ = 23227820928. Its totient is φ = 6935846400.
The previous prime is 13202451077. The next prime is 13202451161. The reversal of 13202451135 is 53115420231.
13202451135 is a `hidden beast` number, since 1 + 3 + 202 + 451 + 1 + 3 + 5 = 666.
It is not a de Polignac number, because 13202451135 - 210 = 13202450111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13202451099 and 13202451108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3089050 + ... + 3093320.
It is an arithmetic number, because the mean of its divisors is an integer number (483912936).
Almost surely, 213202451135 is an apocalyptic number.
13202451135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13202451135 is a deficient number, since it is larger than the sum of its proper divisors (10025369793).
13202451135 is a wasteful number, since it uses less digits than its factorization.
13202451135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5296 (or 5293 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 13202451135 its reverse (53115420231), we get a palindrome (66317871366).
The spelling of 13202451135 in words is "thirteen billion, two hundred two million, four hundred fifty-one thousand, one hundred thirty-five".
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