Base | Representation |
---|---|
bin | 10011001101101000000… |
… | …101011101100011011111 |
3 | 11200012221001200101112101 |
4 | 103031220011131203133 |
5 | 133112434103101421 |
6 | 2450312113145531 |
7 | 164250203135014 |
oct | 23155005354337 |
9 | 4605831611471 |
10 | 1320301222111 |
11 | 469a3368a903 |
12 | 193a7225b2a7 |
13 | 9767200a1c1 |
14 | 47c8d88170b |
15 | 24526342191 |
hex | 1336815d8df |
1320301222111 has 2 divisors, whose sum is σ = 1320301222112. Its totient is φ = 1320301222110.
The previous prime is 1320301222087. The next prime is 1320301222129. The reversal of 1320301222111 is 1112221030231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320301222111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1020301222111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660150611055 + 660150611056.
It is an arithmetic number, because the mean of its divisors is an integer number (660150611056).
Almost surely, 21320301222111 is an apocalyptic number.
1320301222111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320301222111 is an equidigital number, since it uses as much as digits as its factorization.
1320301222111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1320301222111 its reverse (1112221030231), we get a palindrome (2432522252342).
The spelling of 1320301222111 in words is "one trillion, three hundred twenty billion, three hundred one million, two hundred twenty-two thousand, one hundred eleven".
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