Base | Representation |
---|---|
bin | 1100000000100001000011… |
… | …0111000010001101001001 |
3 | 1201202012021122000110010021 |
4 | 3000020100313002031021 |
5 | 3212304232124032223 |
6 | 44025214035220441 |
7 | 2531612645054461 |
oct | 300102067021511 |
9 | 51665248013107 |
10 | 13203012330313 |
11 | 4230403293283 |
12 | 15929ba147721 |
13 | 74a0670b8260 |
14 | 33905a1dcba1 |
15 | 17d6922d865d |
hex | c0210dc2349 |
13203012330313 has 4 divisors (see below), whose sum is σ = 14218628663428. Its totient is φ = 12187395997200.
The previous prime is 13203012330281. The next prime is 13203012330373. The reversal of 13203012330313 is 31303321030231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 738779787529 + 12464232542784 = 859523^2 + 3530472^2 .
It is a cyclic number.
It is not a de Polignac number, because 13203012330313 - 25 = 13203012330281 is a prime.
It is a super-2 number, since 2×132030123303132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13203012330373) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 507808166538 + ... + 507808166563.
It is an arithmetic number, because the mean of its divisors is an integer number (3554657165857).
Almost surely, 213203012330313 is an apocalyptic number.
13203012330313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13203012330313 is a deficient number, since it is larger than the sum of its proper divisors (1015616333115).
13203012330313 is a wasteful number, since it uses less digits than its factorization.
13203012330313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1015616333114.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 13203012330313 its reverse (31303321030231), we get a palindrome (44506333360544).
The spelling of 13203012330313 in words is "thirteen trillion, two hundred three billion, twelve million, three hundred thirty thousand, three hundred thirteen".
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