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13203025103407 is a prime number
BaseRepresentation
bin1100000000100001000110…
…0111110000101000101111
31201202012022112001101111211
43000020101213300220233
53212304243411302112
644025215213055251
72531613161454016
oct300102147605057
951665275041454
1013203025103407
11423040a517957
121592a02487527
1374a06993b0b9
1433905bba5a7d
1517d6934ad0a7
hexc02119f0a2f

13203025103407 has 2 divisors, whose sum is σ = 13203025103408. Its totient is φ = 13203025103406.

The previous prime is 13203025103393. The next prime is 13203025103461. The reversal of 13203025103407 is 70430152030231.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13203025103407 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13203025103207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601512551703 + 6601512551704.

It is an arithmetic number, because the mean of its divisors is an integer number (6601512551704).

Almost surely, 213203025103407 is an apocalyptic number.

13203025103407 is a deficient number, since it is larger than the sum of its proper divisors (1).

13203025103407 is an equidigital number, since it uses as much as digits as its factorization.

13203025103407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 31.

Adding to 13203025103407 its reverse (70430152030231), we get a palindrome (83633177133638).

The spelling of 13203025103407 in words is "thirteen trillion, two hundred three billion, twenty-five million, one hundred three thousand, four hundred seven".