Base | Representation |
---|---|
bin | 10011001101101000101… |
… | …000101011001111111111 |
3 | 11200012221201001101021022 |
4 | 103031220220223033333 |
5 | 133112443434000442 |
6 | 2450313043054355 |
7 | 164250344452652 |
oct | 23155050531777 |
9 | 4605851041238 |
10 | 1320310453247 |
11 | 469a38915345 |
12 | 193a753713bb |
13 | 97673bbcb06 |
14 | 47c90ba5899 |
15 | 245270673d2 |
hex | 13368a2b3ff |
1320310453247 has 2 divisors, whose sum is σ = 1320310453248. Its totient is φ = 1320310453246.
The previous prime is 1320310453193. The next prime is 1320310453261. The reversal of 1320310453247 is 7423540130231.
It is a strong prime.
It is an emirp because it is prime and its reverse (7423540130231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320310453247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320310153247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660155226623 + 660155226624.
It is an arithmetic number, because the mean of its divisors is an integer number (660155226624).
Almost surely, 21320310453247 is an apocalyptic number.
1320310453247 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320310453247 is an equidigital number, since it uses as much as digits as its factorization.
1320310453247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 35.
Adding to 1320310453247 its reverse (7423540130231), we get a palindrome (8743850583478).
The spelling of 1320310453247 in words is "one trillion, three hundred twenty billion, three hundred ten million, four hundred fifty-three thousand, two hundred forty-seven".
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