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13203113202121 is a prime number
BaseRepresentation
bin1100000000100001011011…
…0111110101000111001001
31201202012112122211021020011
43000020112313311013021
53212304433434431441
644025232041231521
72531615311340413
oct300102667650711
951665478737204
1013203113202121
11423045521a807
121592a27a925a1
1374a081c7580b
143390697799b3
1517d69b0b1581
hexc0216df51c9

13203113202121 has 2 divisors, whose sum is σ = 13203113202122. Its totient is φ = 13203113202120.

The previous prime is 13203113202119. The next prime is 13203113202133. The reversal of 13203113202121 is 12120231130231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9345860410000 + 3857252792121 = 3057100^2 + 1963989^2 .

It is a cyclic number.

It is not a de Polignac number, because 13203113202121 - 21 = 13203113202119 is a prime.

Together with 13203113202119, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13203113202092 and 13203113202101.

It is not a weakly prime, because it can be changed into another prime (13203113502121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601556601060 + 6601556601061.

It is an arithmetic number, because the mean of its divisors is an integer number (6601556601061).

Almost surely, 213203113202121 is an apocalyptic number.

It is an amenable number.

13203113202121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13203113202121 is an equidigital number, since it uses as much as digits as its factorization.

13203113202121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 13203113202121 its reverse (12120231130231), we get a palindrome (25323344332352).

The spelling of 13203113202121 in words is "thirteen trillion, two hundred three billion, one hundred thirteen million, two hundred two thousand, one hundred twenty-one".