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132031521120542 = 273904325487127
BaseRepresentation
bin11110000001010011111011…
…111010100110000100011110
3122022111002102201101222012212
4132001103323322212010132
5114301201023401324132
61144450235442000422
736544651114260251
oct3601237372460436
9568432381358185
10132031521120542
113908428768845a
1212984715346112
13588969938a074
1424865070d7098
15103e6999bc5b2
hex7814fbea611e

132031521120542 has 8 divisors (see below), whose sum is σ = 200760258142416. Its totient is φ = 65111435073072.

The previous prime is 132031521120529. The next prime is 132031521120563. The reversal of 132031521120542 is 245021125130231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 132031521120499 and 132031521120508.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 452162743418 + ... + 452162743709.

It is an arithmetic number, because the mean of its divisors is an integer number (25095032267802).

Almost surely, 2132031521120542 is an apocalyptic number.

132031521120542 is a deficient number, since it is larger than the sum of its proper divisors (68728737021874).

132031521120542 is an equidigital number, since it uses as much as digits as its factorization.

132031521120542 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 904325487202.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 132031521120542 its reverse (245021125130231), we get a palindrome (377052646250773).

The spelling of 132031521120542 in words is "one hundred thirty-two trillion, thirty-one billion, five hundred twenty-one million, one hundred twenty thousand, five hundred forty-two".

Divisors: 1 2 73 146 904325487127 1808650974254 66015760560271 132031521120542