Base | Representation |
---|---|
bin | 11110000001010011111101… |
… | …010010010101101100000000 |
3 | 122022111002111022200120102212 |
4 | 132001103331102111230000 |
5 | 114301201100243401422 |
6 | 1144450242023001252 |
7 | 36544651513630235 |
oct | 3601237522255400 |
9 | 568432438616385 |
10 | 132031544122112 |
11 | 39084299668918 |
12 | 12984720b99228 |
13 | 58896a108176b |
14 | 248650a1a378c |
15 | 103e69ba129e2 |
hex | 7814fd495b00 |
132031544122112 has 36 divisors (see below), whose sum is σ = 267157577597400. Its totient is φ = 65111446407168.
The previous prime is 132031544122087. The next prime is 132031544122117. The reversal of 132031544122112 is 211221445130231.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is not an unprimeable number, because it can be changed into a prime (132031544122117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3532503362 + ... + 3532540737.
It is an arithmetic number, because the mean of its divisors is an integer number (7421043822150).
Almost surely, 2132031544122112 is an apocalyptic number.
It is an amenable number.
132031544122112 is an abundant number, since it is smaller than the sum of its proper divisors (135126033475288).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132031544122112 is an frugal number, since it uses more digits than its factorization.
132031544122112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7065044188 (or 7065044174 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 132031544122112 its reverse (211221445130231), we get a palindrome (343252989252343).
The spelling of 132031544122112 in words is "one hundred thirty-two trillion, thirty-one billion, five hundred forty-four million, one hundred twenty-two thousand, one hundred twelve".
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