Base | Representation |
---|---|
bin | 111101011110110111… |
… | …0100100111001001001 |
3 | 110121210112201202112221 |
4 | 1322331232210321021 |
5 | 4130400210404231 |
6 | 140353230334041 |
7 | 12352610344402 |
oct | 1727556447111 |
9 | 417715652487 |
10 | 132032122441 |
11 | 50aa376686a |
12 | 2170935a321 |
13 | c5b1bb7c4b |
14 | 65673269a9 |
15 | 367b46dd11 |
hex | 1ebdba4e49 |
132032122441 has 4 divisors (see below), whose sum is σ = 132036601984. Its totient is φ = 132027642900.
The previous prime is 132032122433. The next prime is 132032122447. The reversal of 132032122441 is 144221230231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 144221230231 = 13 ⋅11093940787.
It is a cyclic number.
It is not a de Polignac number, because 132032122441 - 23 = 132032122433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132032122447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2195265 + ... + 2254606.
It is an arithmetic number, because the mean of its divisors is an integer number (33009150496).
Almost surely, 2132032122441 is an apocalyptic number.
It is an amenable number.
132032122441 is a deficient number, since it is larger than the sum of its proper divisors (4479543).
132032122441 is an equidigital number, since it uses as much as digits as its factorization.
132032122441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4479542.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 132032122441 its reverse (144221230231), we get a palindrome (276253352672).
The spelling of 132032122441 in words is "one hundred thirty-two billion, thirty-two million, one hundred twenty-two thousand, four hundred forty-one".
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