Base | Representation |
---|---|
bin | 10011001101101001010… |
… | …101000111011101011010 |
3 | 11200012222111222020220110 |
4 | 103031221111013131122 |
5 | 133113004424300010 |
6 | 2450314140505150 |
7 | 164250545463432 |
oct | 23155125073532 |
9 | 4605874866813 |
10 | 1320322103130 |
11 | 469a44452048 |
12 | 193a7924b1b6 |
13 | 9767643b634 |
14 | 47c925592c2 |
15 | 245280b9120 |
hex | 1336954775a |
1320322103130 has 32 divisors (see below), whose sum is σ = 3181102922304. Its totient is φ = 350715908096.
The previous prime is 1320322103119. The next prime is 1320322103131. The reversal of 1320322103130 is 313012230231.
It is a junction number, because it is equal to n+sod(n) for n = 1320322103097 and 1320322103106.
It is not an unprimeable number, because it can be changed into a prime (1320322103131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 85616292 + ... + 85631711.
It is an arithmetic number, because the mean of its divisors is an integer number (99409466322).
Almost surely, 21320322103130 is an apocalyptic number.
1320322103130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1320322103130 is an abundant number, since it is smaller than the sum of its proper divisors (1860780819174).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1320322103130 is a wasteful number, since it uses less digits than its factorization.
1320322103130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 171248270.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1320322103130 its reverse (313012230231), we get a palindrome (1633334333361).
The spelling of 1320322103130 in words is "one trillion, three hundred twenty billion, three hundred twenty-two million, one hundred three thousand, one hundred thirty".
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