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1320322320133 is a prime number
BaseRepresentation
bin10011001101101001010…
…101111100011100000101
311200012222112101021120121
4103031221111330130011
5133113010003221013
62450314145301541
7164250550356205
oct23155125743405
94605875337517
101320322320133
11469a44590093
12193a793348b1
13976764b633b
1447c925b4405
152452810d58d
hex1336957c705

1320322320133 has 2 divisors, whose sum is σ = 1320322320134. Its totient is φ = 1320322320132.

The previous prime is 1320322320101. The next prime is 1320322320137. The reversal of 1320322320133 is 3310232230231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 823942890369 + 496379429764 = 907713^2 + 704542^2 .

It is an emirp because it is prime and its reverse (3310232230231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1320322320133 - 25 = 1320322320101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1320322320098 and 1320322320107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320322320137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660161160066 + 660161160067.

It is an arithmetic number, because the mean of its divisors is an integer number (660161160067).

Almost surely, 21320322320133 is an apocalyptic number.

It is an amenable number.

1320322320133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320322320133 is an equidigital number, since it uses as much as digits as its factorization.

1320322320133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 1320322320133 its reverse (3310232230231), we get a palindrome (4630554550364).

The spelling of 1320322320133 in words is "one trillion, three hundred twenty billion, three hundred twenty-two million, three hundred twenty thousand, one hundred thirty-three".