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132032505036373 is a prime number
BaseRepresentation
bin11110000001010100110110…
…100011111011111001010101
3122022111011222021211001222221
4132001110312203323321111
5114301210032242130443
61144450521230422341
736545014362361444
oct3601246643737125
9568434867731887
10132032505036373
1139084742015a37
121298494a9619b1
1358897c5185296
14248659ba58d5b
15103e706072eed
hex7815368fbe55

132032505036373 has 2 divisors, whose sum is σ = 132032505036374. Its totient is φ = 132032505036372.

The previous prime is 132032505036281. The next prime is 132032505036409. The reversal of 132032505036373 is 373630505230231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111454324039249 + 20578180997124 = 10557193^2 + 4536318^2 .

It is a cyclic number.

It is not a de Polignac number, because 132032505036373 - 225 = 132032471481941 is a prime.

It is a super-2 number, since 2×1320325050363732 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132032505036073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016252518186 + 66016252518187.

It is an arithmetic number, because the mean of its divisors is an integer number (66016252518187).

Almost surely, 2132032505036373 is an apocalyptic number.

It is an amenable number.

132032505036373 is a deficient number, since it is larger than the sum of its proper divisors (1).

132032505036373 is an equidigital number, since it uses as much as digits as its factorization.

132032505036373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1020600, while the sum is 43.

The spelling of 132032505036373 in words is "one hundred thirty-two trillion, thirty-two billion, five hundred five million, thirty-six thousand, three hundred seventy-three".