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132033030504404 = 22971272679459179
BaseRepresentation
bin11110000001010101010101…
…111000011011111111010100
3122022111020022220120121121212
4132001111111320123333110
5114301212121302120104
61144451045321200552
736545033402650301
oct3601252570337724
9568436286517555
10132033030504404
1139084991697937
1212984a76930158
135889879cb6603
14248660b7600a8
15103e73726c36e
hex781555e1bfd4

132033030504404 has 24 divisors (see below), whose sum is σ = 235277951677440. Its totient is φ = 64821476434176.

The previous prime is 132033030504377. The next prime is 132033030504439. The reversal of 132033030504404 is 404405030330231.

It is a super-2 number, since 2×1320330305044042 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1339680314 + ... + 1339778865.

It is an arithmetic number, because the mean of its divisors is an integer number (9803247986560).

Almost surely, 2132033030504404 is an apocalyptic number.

It is an amenable number.

132033030504404 is a deficient number, since it is larger than the sum of its proper divisors (103244921173036).

132033030504404 is a wasteful number, since it uses less digits than its factorization.

132033030504404 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2679459407 (or 2679459405 counting only the distinct ones).

The product of its (nonzero) digits is 51840, while the sum is 32.

Adding to 132033030504404 its reverse (404405030330231), we get a palindrome (536438060834635).

The spelling of 132033030504404 in words is "one hundred thirty-two trillion, thirty-three billion, thirty million, five hundred four thousand, four hundred four".

Divisors: 1 2 4 97 127 194 254 388 508 12319 24638 49276 2679459179 5358918358 10717836716 259907540363 340291315733 519815080726 680582631466 1039630161452 1361165262932 33008257626101 66016515252202 132033030504404