132033161044597 has 2 divisors, whose sum is σ = 132033161044598. Its totient is φ = 132033161044596.

The previous prime is 132033161044511. The next prime is 132033161044627. The reversal of 132033161044597 is 795440161330231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125581921719556 + 6451239325041 = 11206334^2 + 2539929^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132033161044597 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132033161044597.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132033161044397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016580522298 + 66016580522299.

It is an arithmetic number, because the mean of its divisors is an integer number (66016580522299).

Almost surely, 2^{132033161044597} is an apocalyptic number.

It is an amenable number.

132033161044597 is a deficient number, since it is larger than the sum of its proper divisors (1).

132033161044597 is an equidigital number, since it uses as much as digits as its factorization.

132033161044597 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1632960, while the sum is 49.

The spelling of 132033161044597 in words is "one hundred thirty-two trillion, thirty-three billion, one hundred sixty-one million, forty-four thousand, five hundred ninety-seven".