Base | Representation |
---|---|
bin | 11000100101111101… |
… | …10000000000011110 |
3 | 1021002011102020100022 |
4 | 30102332300000132 |
5 | 204020023410332 |
6 | 10022053232142 |
7 | 645122356352 |
oct | 142276600036 |
9 | 37064366308 |
10 | 13203341342 |
11 | 5665a3a854 |
12 | 2685932652 |
13 | 1325558b19 |
14 | 8d377b462 |
15 | 52421b212 |
hex | 312fb001e |
13203341342 has 4 divisors (see below), whose sum is σ = 19805012016. Its totient is φ = 6601670670.
The previous prime is 13203341341. The next prime is 13203341353. The reversal of 13203341342 is 24314330231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24314330231 = 137 ⋅177476863.
It is a super-3 number, since 3×132033413423 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13203341341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3300835334 + ... + 3300835337.
It is an arithmetic number, because the mean of its divisors is an integer number (4951253004).
Almost surely, 213203341342 is an apocalyptic number.
13203341342 is a deficient number, since it is larger than the sum of its proper divisors (6601670674).
13203341342 is an equidigital number, since it uses as much as digits as its factorization.
13203341342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6601670673.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 13203341342 its reverse (24314330231), we get a palindrome (37517671573).
The spelling of 13203341342 in words is "thirteen billion, two hundred three million, three hundred forty-one thousand, three hundred forty-two".
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