132033512103113 has 2 divisors, whose sum is σ = 132033512103114. Its totient is φ = 132033512103112.

The previous prime is 132033512103019. The next prime is 132033512103133. The reversal of 132033512103113 is 311301215330231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80194836894649 + 51838675208464 = 8955157^2 + 7199908^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132033512103113 is a prime.

It is not a weakly prime, because it can be changed into another prime (132033512103133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016756051556 + 66016756051557.

It is an arithmetic number, because the mean of its divisors is an integer number (66016756051557).

Almost surely, 2^{132033512103113} is an apocalyptic number.

It is an amenable number.

132033512103113 is a deficient number, since it is larger than the sum of its proper divisors (1).

132033512103113 is an equidigital number, since it uses as much as digits as its factorization.

132033512103113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4860, while the sum is 29.

Adding to 132033512103113 its reverse (311301215330231), we get a palindrome (443334727433344).

The spelling of 132033512103113 in words is "one hundred thirty-two trillion, thirty-three billion, five hundred twelve million, one hundred three thousand, one hundred thirteen".