Base | Representation |
---|---|
bin | 11110000001010101110100… |
… | …010011111110100010110111 |
3 | 122022111021122111020112020011 |
4 | 132001111310103332202313 |
5 | 114301214143001242221 |
6 | 1144451212115521051 |
7 | 36545052142305211 |
oct | 3601256423764267 |
9 | 568437574215204 |
10 | 132033541040311 |
11 | 390851238a0039 |
12 | 12984b998b9187 |
13 | 588992b9ba171 |
14 | 24866594995b1 |
15 | 103e766eb71e1 |
hex | 7815744fe8b7 |
132033541040311 has 2 divisors, whose sum is σ = 132033541040312. Its totient is φ = 132033541040310.
The previous prime is 132033541040299. The next prime is 132033541040473. The reversal of 132033541040311 is 113040145330231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132033541040311 - 229 = 132033004169399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132033541040711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016770520155 + 66016770520156.
It is an arithmetic number, because the mean of its divisors is an integer number (66016770520156).
Almost surely, 2132033541040311 is an apocalyptic number.
132033541040311 is a deficient number, since it is larger than the sum of its proper divisors (1).
132033541040311 is an equidigital number, since it uses as much as digits as its factorization.
132033541040311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 132033541040311 its reverse (113040145330231), we get a palindrome (245073686370542).
The spelling of 132033541040311 in words is "one hundred thirty-two trillion, thirty-three billion, five hundred forty-one million, forty thousand, three hundred eleven".
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