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13203421040434 = 211047597602111
BaseRepresentation
bin1100000000100010100100…
…1110001000111100110010
31201202020100010002002000011
43000020221032020330302
53212311101241243214
644025322355245134
72531626040044252
oct300105116107462
951666303062004
1013203421040434
1142305a2a68239
121592ab2ba97aa
1374a100989271
143390985cd962
1517d6b811cac4
hexc0229388f32

13203421040434 has 8 divisors (see below), whose sum is σ = 19806924400128. Its totient is φ = 6601112907060.

The previous prime is 13203421040417. The next prime is 13203421040437. The reversal of 13203421040434 is 43404012430231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13203421040396 and 13203421040405.

It is not an unprimeable number, because it can be changed into a prime (13203421040437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 298778962 + ... + 298823149.

It is an arithmetic number, because the mean of its divisors is an integer number (2475865550016).

Almost surely, 213203421040434 is an apocalyptic number.

13203421040434 is a deficient number, since it is larger than the sum of its proper divisors (6603503359694).

13203421040434 is a wasteful number, since it uses less digits than its factorization.

13203421040434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 597613160.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 13203421040434 its reverse (43404012430231), we get a palindrome (56607433470665).

The spelling of 13203421040434 in words is "thirteen trillion, two hundred three billion, four hundred twenty-one million, forty thousand, four hundred thirty-four".

Divisors: 1 2 11047 22094 597602111 1195204222 6601710520217 13203421040434