13203440113 has 4 divisors (see below), whose sum is σ = 13629357568. Its totient is φ = 12777522660.

The previous prime is 13203440111. The next prime is 13203440137. The reversal of 13203440113 is 31104430231.

13203440113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13203440113 - 2¹ = 13203440111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13203440111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 212958681 + ... + 212958742.

It is an arithmetic number, because the mean of its divisors is an integer number (3407339392).

Almost surely, 2^13203440113 is an apocalyptic number.

It is an amenable number.

13203440113 is a deficient number, since it is larger than the sum of its proper divisors (425917455).

13203440113 is an equidigital number, since it uses as much as digits as its factorization.

13203440113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 425917454.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 13203440113 its reverse (31104430231), we get a palindrome (44307870344).

The spelling of 13203440113 in words is "thirteen billion, two hundred three million, four hundred forty thousand, one hundred thirteen".