13203541410133 has 4 divisors (see below), whose sum is σ = 13203554107968. Its totient is φ = 13203528712300.

The previous prime is 13203541410023. The next prime is 13203541410139. The reversal of 13203541410133 is 33101414530231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13203541410133 - 2²¹ = 13203539312981 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13203541410095 and 13203541410104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13203541410139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4634941 + ... + 6920242.

It is an arithmetic number, because the mean of its divisors is an integer number (3300888526992).

Almost surely, 2^{13203541410133} is an apocalyptic number.

It is an amenable number.

13203541410133 is a deficient number, since it is larger than the sum of its proper divisors (12697835).

13203541410133 is a wasteful number, since it uses less digits than its factorization.

13203541410133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12697834.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 13203541410133 its reverse (33101414530231), we get a palindrome (46304955940364).

The spelling of 13203541410133 in words is "thirteen trillion, two hundred three billion, five hundred forty-one million, four hundred ten thousand, one hundred thirty-three".