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132039569609 is a prime number
BaseRepresentation
bin111101011111000101…
…0111111000011001001
3110121211001202010010222
41322332022333003021
54130404112211414
6140354054115425
712353030552303
oct1727612770311
9417731663128
10132039569609
1150aa7992a52
122170b94bb75
13c5b35c485c
146568304973
15367be4068e
hex1ebe2bf0c9

132039569609 has 2 divisors, whose sum is σ = 132039569610. Its totient is φ = 132039569608.

The previous prime is 132039569593. The next prime is 132039569611. The reversal of 132039569609 is 906965930231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107094526009 + 24945043600 = 327253^2 + 157940^2 .

It is an emirp because it is prime and its reverse (906965930231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132039569609 - 24 = 132039569593 is a prime.

Together with 132039569611, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132039569699) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66019784804 + 66019784805.

It is an arithmetic number, because the mean of its divisors is an integer number (66019784805).

Almost surely, 2132039569609 is an apocalyptic number.

It is an amenable number.

132039569609 is a deficient number, since it is larger than the sum of its proper divisors (1).

132039569609 is an equidigital number, since it uses as much as digits as its factorization.

132039569609 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2361960, while the sum is 53.

The spelling of 132039569609 in words is "one hundred thirty-two billion, thirty-nine million, five hundred sixty-nine thousand, six hundred nine".