13204000125 has 48 divisors (see below), whose sum is σ = 25055209920. Its totient is φ = 6671484000.

The previous prime is 13204000099. The next prime is 13204000127. The reversal of 13204000125 is 52100040231.

It is not a de Polignac number, because 13204000125 - 2⁵ = 13204000093 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13204000098 and 13204000107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13204000127) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 287491 + ... + 330240.

It is an arithmetic number, because the mean of its divisors is an integer number (521983540).

Almost surely, 2^13204000125 is an apocalyptic number.

13204000125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

13204000125 is a deficient number, since it is larger than the sum of its proper divisors (11851209795).

13204000125 is a wasteful number, since it uses less digits than its factorization.

13204000125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 617771 (or 617758 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 18.

Adding to 13204000125 its reverse (52100040231), we get a palindrome (65304040356).

The spelling of 13204000125 in words is "thirteen billion, two hundred four million, one hundred twenty-five", and thus it is an aban number.