Base | Representation |
---|---|
bin | 1100000000100100110001… |
… | …0110000000001110101011 |
3 | 1201202021212011212210020111 |
4 | 3000021030112000032223 |
5 | 3212313303114220202 |
6 | 44025501045235151 |
7 | 2531646453520135 |
oct | 300111426001653 |
9 | 51667764783214 |
10 | 13204010304427 |
11 | 4230875652a78 |
12 | 1593038402ab7 |
13 | 74a195a96297 |
14 | 339112980055 |
15 | 17d6eec196d7 |
hex | c024c5803ab |
13204010304427 has 2 divisors, whose sum is σ = 13204010304428. Its totient is φ = 13204010304426.
The previous prime is 13204010304367. The next prime is 13204010304469. The reversal of 13204010304427 is 72440301040231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13204010304427 - 27 = 13204010304299 is a prime.
It is not a weakly prime, because it can be changed into another prime (13204010304127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6602005152213 + 6602005152214.
It is an arithmetic number, because the mean of its divisors is an integer number (6602005152214).
Almost surely, 213204010304427 is an apocalyptic number.
13204010304427 is a deficient number, since it is larger than the sum of its proper divisors (1).
13204010304427 is an equidigital number, since it uses as much as digits as its factorization.
13204010304427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 13204010304427 its reverse (72440301040231), we get a palindrome (85644311344658).
The spelling of 13204010304427 in words is "thirteen trillion, two hundred four billion, ten million, three hundred four thousand, four hundred twenty-seven".
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