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13204011501 = 334111927743
BaseRepresentation
bin11000100110000010…
…10011100111101101
31021002012200021122000
430103001103213231
5204020211332001
610022115442513
7645131150232
oct142301234755
937065607560
1013204011501
1156663582aa
122685bb6439
131325731b75
148d38b3789
155242eea86
hex3130539ed

13204011501 has 16 divisors (see below), whose sum is σ = 20038609920. Its totient is φ = 8587974240.

The previous prime is 13204011497. The next prime is 13204011517. The reversal of 13204011501 is 10511040231.

13204011501 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13204011501 - 22 = 13204011497 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13204011551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5962765 + ... + 5964978.

It is an arithmetic number, because the mean of its divisors is an integer number (1252413120).

Almost surely, 213204011501 is an apocalyptic number.

It is an amenable number.

13204011501 is a deficient number, since it is larger than the sum of its proper divisors (6834598419).

13204011501 is a wasteful number, since it uses less digits than its factorization.

13204011501 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11927793 (or 11927787 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

Adding to 13204011501 its reverse (10511040231), we get a palindrome (23715051732).

The spelling of 13204011501 in words is "thirteen billion, two hundred four million, eleven thousand, five hundred one".

Divisors: 1 3 9 27 41 123 369 1107 11927743 35783229 107349687 322049061 489037463 1467112389 4401337167 13204011501