Base | Representation |
---|---|
bin | 11110000001011101001001… |
… | …000000000000100110100111 |
3 | 122022112000221111101112100102 |
4 | 132001131021000000212213 |
5 | 114301331244001221132 |
6 | 1144454552253134315 |
7 | 36545451043135316 |
oct | 3601351100004647 |
9 | 568460844345312 |
10 | 132041404320167 |
11 | 39088499476631 |
12 | 1298661318a39b |
13 | 588a5b2b00a94 |
14 | 2486ba393427d |
15 | 103ea774a7c62 |
hex | 7817490009a7 |
132041404320167 has 2 divisors, whose sum is σ = 132041404320168. Its totient is φ = 132041404320166.
The previous prime is 132041404320157. The next prime is 132041404320269. The reversal of 132041404320167 is 761023404140231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132041404320167 - 24 = 132041404320151 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132041404320167.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132041404320127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66020702160083 + 66020702160084.
It is an arithmetic number, because the mean of its divisors is an integer number (66020702160084).
Almost surely, 2132041404320167 is an apocalyptic number.
132041404320167 is a deficient number, since it is larger than the sum of its proper divisors (1).
132041404320167 is an equidigital number, since it uses as much as digits as its factorization.
132041404320167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 38.
Adding to 132041404320167 its reverse (761023404140231), we get a palindrome (893064808460398).
The spelling of 132041404320167 in words is "one hundred thirty-two trillion, forty-one billion, four hundred four million, three hundred twenty thousand, one hundred sixty-seven".
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