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1320421535539 is a prime number
BaseRepresentation
bin10011001101101111010…
…000011010111100110011
311200020020110001221112021
4103031233100122330303
5133113210403114124
62450332052012311
7164253163603021
oct23155720327463
94606213057467
101320421535539
11469a95596097
12193aa6601097
1397690c13992
1447ca183d711
1524531baa7e4
hex1336f41af33

1320421535539 has 2 divisors, whose sum is σ = 1320421535540. Its totient is φ = 1320421535538.

The previous prime is 1320421535519. The next prime is 1320421535569. The reversal of 1320421535539 is 9355351240231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1320421535539 - 211 = 1320421533491 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1320421535495 and 1320421535504.

It is not a weakly prime, because it can be changed into another prime (1320421535519) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660210767769 + 660210767770.

It is an arithmetic number, because the mean of its divisors is an integer number (660210767770).

Almost surely, 21320421535539 is an apocalyptic number.

1320421535539 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320421535539 is an equidigital number, since it uses as much as digits as its factorization.

1320421535539 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486000, while the sum is 43.

The spelling of 1320421535539 in words is "one trillion, three hundred twenty billion, four hundred twenty-one million, five hundred thirty-five thousand, five hundred thirty-nine".